Answer :
Final answer:
Examining the balanced equation MnO2 + 4 HCl → MnCl2 + Cl2 + 2 H2O reveals that 1 mole of MnO2 reacts with 4 moles of HCl to yield 1 mole of Cl2. By calculating the moles of HCl (1.42 mol) and using the molar mass of Cl2 (70.9 g/mol), we determine that 5.68 moles of Cl2 produce 402.712 g.
Explanation:
By examining the balanced chemical equation:
MnO2 + 4 HCl → MnCl2 + Cl2 + 2 H2O
We can deduce that 1 mole of MnO2 engages with 4 moles of HCl to yield 1 mole of Cl2.
Therefore, to ascertain the moles of Cl2 generated, an initial calculation of the moles of available HCl is essential.
Considering the molar mass of HCl to be 36.5 g/mol, we can determine the moles of HCl by dividing the given mass (51.7 g) by the molar mass:
moles of HCl = 51.7 g / 36.5 g/mol = 1.42 mol
Given the stoichiometric ratio between HCl and Cl2 as 4:1, the moles of Cl2 produced can be derived as follows:
moles of Cl2 = (4/1) × moles of HCl = 4 × 1.42 mol = 5.68 mol
To compute the mass of Cl2 generated, we can employ the molar mass of Cl2, which is 70.9 g/mol:
mass of Cl2 = moles of Cl2 × molar mass = 5.68 mol × 70.9 g/mol = 402.712 g
This comprehensive analysis illustrates the step-by-step procedure for determining the quantity of Cl2 produced based on the given chemical reaction and mass of HCl.
Learn more about balanced equation
https://brainly.com/question/34410295
#SPJ11
