High School

When the velocity of a 5000-kg truck whose K.E is 360 kJ, the truck's maximum distance covered is:

A. 156 km/h
B. 43 km/h
C. 35 km/h
D. 40 km/h

Answer :

Final answer:

The velocity of the truck is approximately 43 km/h, determined using the kinetic energy formula and then converting the velocity from m/s to km/h. B. 43 km/h.

Explanation:

The velocity of a truck can be determined based on its kinetic energy (KE) using the formula KE = 0.5 * m * v^2, where m is the mass and v is the velocity. The given kinetic energy is 360 KJ (or 360,000 J), and the mass of the truck is 5000 kg. Rearranging the formula to isolate velocity gives v = sqrt((2*KE)/m).

Substituting the given values into this formula results in v = sqrt((2*360000)/5000) = sqrt(144) = 12 m/s. To convert this to km/h, we multiply by 3.6, which gives 43.2 km/h. The closest available answer choice is B. 43 km/h.

Learn more about Velocity from Kinetic Energy here:

https://brainly.com/question/32767911

#SPJ11