High School

Find the greatest number that divides 62, 95, and 158, leaving remainders of 2, 5, and 8, respectively.

Answer :

Final answer:

To find the greatest number that divides 62, 95, and 158 leaving remainders of 2, 5, and 8 respectively, we first subtract these remainders from each number. That gives us 60, 90, and 150. The greatest common divisor (GCD) of these numbers is the solution. The GCD of 60, 90, and 150 is 30. Therefore, 30 divides into 62, 95, and 158 leaving the specified remainders.

Explanation:

In solving this math problem, we need to find a number that would leave specific remainders when taken away from each of these numbers. So, if a number leaves a remainder of 2 when subtracted from 62, that same number would have to be 62 - 2 = 60. Similarly, we do 95 - 5 = 90 and 158 - 8 = 150.

Now, we need to find the greatest common divisor (GCD) of 60, 90, and 150. The GCD is the largest number that can divide each of these numbers without any remainder.

You can find the GCD by factoring each number and multiplying the common factors together. In this case, the GCD of 60, 90, and 150 is 30. Therefore, 30 is the greatest number that will divide into 62, 95, and 158 leaving remainders of 2, 5, and 8 respectively.

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