High School

The distance at which Nilesh can throw a javelin is inversely proportional to the weight of the javelin. Nilesh can throw a 1.5-pound javelin exactly 260 feet. How far would Nilesh be able to throw a two-pound javelin, in feet, assuming all other factors remain constant? (Disregard units when inputting your answer.) A) 195 B) 205 C) 207 D) 211

Answer :

Final answer:

Nilesh's javelin throwing distance is inversely proportional to the weight of the javelin. After calculating the value of the constant of proportionality from the given information, we can determine that Nilesh can throw a two-pound javelin 195 feet.

Explanation:

In this case, we are dealing with a situation of inverse proportionality between the weight of a javelin and the distance Nilesh can throw it. Mathematically, this relationship can be represented by the equation d = k/w, where 'd' stands for distance, 'w' stands for the weight of the javelin, and 'k' is a constant of proportionality.

We can find the value of 'k' using the information given in the problem: Nilesh can throw a 1.5-pound javelin exactly 260 feet. Therefore, k = d * w = 260 * 1.5 = 390.

Now that we know the constant of proportionality, we can find out how far Nilesh can throw a two-pound javelin using the same equation: d = k/w = 390/2 = 195 feet. Therefore, the correct answer is A) 195.

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