Answer :
Sure, let's solve the long division problem [tex]\( 7 \div 147 \)[/tex] step by step.
1. Divide: First, you look at how many times 7 can fit into the first digit of 147, which is 1. Since 7 is larger than 1, it fits 0 times. So, we move to the next digit, making it 14.
2. Divide: Now, consider how many times 7 can fit into 14. 7 fits into 14 exactly 2 times because [tex]\(7 \times 2 = 14\)[/tex].
3. Subtract: After dividing, we subtract the result from 14.
[tex]\[
14 - 14 = 0
\][/tex]
4. Bring down: Now, bring down the next digit which is 7, making the number 07.
5. Divide: Now, see how many times 7 fits into 07. 7 fits into 7 exactly 1 time because [tex]\(7 \times 1 = 7\)[/tex].
6. Subtract: After dividing, we subtract 7 from 7.
[tex]\[
7 - 7 = 0
\][/tex]
7. No remainder: Since there are no more digits to bring down and the result of our subtraction is 0, the process is complete.
Therefore, the quotient is 21, and the remainder is 0.
The result of dividing 147 by 7 is [tex]\(21\)[/tex] with a remainder of [tex]\(0\)[/tex].
1. Divide: First, you look at how many times 7 can fit into the first digit of 147, which is 1. Since 7 is larger than 1, it fits 0 times. So, we move to the next digit, making it 14.
2. Divide: Now, consider how many times 7 can fit into 14. 7 fits into 14 exactly 2 times because [tex]\(7 \times 2 = 14\)[/tex].
3. Subtract: After dividing, we subtract the result from 14.
[tex]\[
14 - 14 = 0
\][/tex]
4. Bring down: Now, bring down the next digit which is 7, making the number 07.
5. Divide: Now, see how many times 7 fits into 07. 7 fits into 7 exactly 1 time because [tex]\(7 \times 1 = 7\)[/tex].
6. Subtract: After dividing, we subtract 7 from 7.
[tex]\[
7 - 7 = 0
\][/tex]
7. No remainder: Since there are no more digits to bring down and the result of our subtraction is 0, the process is complete.
Therefore, the quotient is 21, and the remainder is 0.
The result of dividing 147 by 7 is [tex]\(21\)[/tex] with a remainder of [tex]\(0\)[/tex].
