Answer :
Final answer:
Given the [H₃O⁺] in a Cabernet Sauvignon wine, the [OH⁻] is calculated using the equation [OH⁻] = (1.0 x 10⁻¹⁴) / [H₃O⁺]. The [OH⁻] equals to (A) 1.69 x 10⁻¹¹ M.
Explanation:
This question deals with the calculation of hydroxide ion concentration [OH⁻] given the hydronium ion concentration [H₃O⁺] in a Cabernet Sauvignon wine. In any aqueous solution at 25 degrees Celsius, the product of the [H₃O⁺] and [OH⁻] concentrations always equals 1.0 x 10⁻¹⁴. This is also known as the ion product of water.
From the question, we have [H₃O⁺] = 5.9 x 10⁻⁴ M. Therefore, to calculate the [OH⁻], we would follow the equation:
[OH⁻]= (1.0 x 10⁻¹⁴) / (5.9 x 10⁻⁴ M)= 1.69 x 10⁻¹¹ M
Hence, the [OH⁻] in the Cabernet Sauvignon wine is 1.69 x 10⁻¹¹ M, which corresponds to option A).
Learn more about Ion product here:
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