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The space between two square flat parallel plates is filled with oil. Each side of the plate is 600 mm. The thickness of the oil film is 12.5 mm. The upper plate, which moves at 2.5 m/s, requires a force of 98.1 N to maintain the speed.

Determine:
I. The dynamic viscosity of the oil in poise.
II. The kinematic viscosity of the oil in stokes if the specific gravity of the oil is 0.95.

Answer :

The dynamic viscosity of the oil in poise is 13.625 pois

The kinematic viscosity of the oil in strokes is 14.34

How to solve for the dynamic viscosity

F viscous is given as n* ΔFr / Δy

where n = F * Δy / A * ΔVn

We have to define the terms of the formula

Δy = 12.5 x 10⁻³

ΔVr = 2.5m /s

A = 60 x 60 cm² = 0.36m

F = 98.1 n

We have to put the values in the formula

98.1 n * 12.5 x 10⁻³ / 0.36m * 2.5m /s

n = 1.3625 ns / m²

The kinematic viscosity of the oil in strokes if the specific gravity of the oil is 0.95

y = n / e

n = 1.3625

e = 0.95 x 10³

y = 1.3625 / 0.95 x 10³

= 1.434 x 10⁻³

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