Answer :
Final answer:
The final temperature of the mixture of 50 grams of water at 0 degrees and 250 grams of water at 90 degrees, according to the rule of heat exchange, is 75 degrees Celsius, making option 3 the correct one.
Explanation:
This question is about the mix of two water bodies at different temperatures. The resulting temperature can be determined using the formula for heat exchange, which states that the heat lost by the hot water equals the heat gained by the cold water. In mathematical terms, m1*c*(Tfinal-Tinitial) = -m2*c*(Tfinal-Tinitial), where m1 and m2 are the masses of the two bodies of water, c is the specific heat capacity of water (which is cancelled out in this case because both are water), and Tfinal and Tinitial are the final and initial temperatures, respectively. In this case, m1 is 50g, Tinitial1 is 0°C, m2 is 250g, and Tinitial2 is 90°C. Solve the equation for Tfinal to obtain the final temperature.
Therefore, your equation will look something like this: 50g*(Tfinal-0°C) = -250g*(Tfinal-90°C). Solving for Tfinal, you get 75 degrees Celsius.
Thus, option 3 is the correct one.
Learn more about Heat exchange here:
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