You attach a small paper clip to a new packet of Taco Bell Mild Sauce, as shown in the video. The packet and paper clip are floating because there is a small air bubble inside the sauce packet.

Suppose the air bubble is initially 0.286 in volume. The pressure inside the water bottle is 98.1 kPa, so the air bubble is also at that same pressure. You then squeeze the bottle to increase the pressure, and the air bubble shrinks to 0.0829 because of Boyle's Law.

Calculate: What is the new pressure in the bottle while you are squeezing? (in kPa)

Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when the temperature is held constant, was used to calculate the new pressure in the bottle when it is squeezed. The initial conditions were a pressure of 98.1kPa and a volume of 0.286. After the squeezing the bottle, the volume was reduced to 0.0829, resulting in a new pressure of approximately 337.7kPa.

The question pertains to the application of Boyle's Law, a fundamental principle in physics. Boyle's Law states that the pressure and volume of a gas have an inverse relationship when the temperature is held constant.

In this case, you squeezed the bottle, decreasing the volume of the air bubble from 0.286 in volume to 0.0829 in volume. We can set up the equation representing Boyle's Law like this:

P1*V1 = P2*V2, where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.

Substituting given values, we find

98.1kPa * 0.286 = P2 * 0.0829.

Solving this for P2 (by dividing both sides of the equation by 0.0829), we find that the new pressure in the bottle when you are squeezing it is approximately 337.7 kPa.

Learn more about Boyle's Law here:

https://brainly.com/question/21184611

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