Answer :
Final answer:
A 14NH3 molecule is a symmetric rotor with a bond length of 101.2 pm and an HNH bond angle of 106.7°. The rotational terms for this molecule can be determined using the rotational term formula, which takes into account the quantum numbers J and K, the rotational constant H, and the shape and symmetry of the molecule.
Explanation:
A symmetric rotor refers to a molecule that has a symmetric shape and rotates freely around its center of mass. In this case, the 14NH3 molecule falls under this category. The HNH bond angle of 106.7° suggests that it is not exactly 180° due to the lone pair repulsion, but it is close to that value. The bond length of 101.2 pm represents the distance between the nitrogen and hydrogen atoms.
When calculating the rotational terms for a symmetric rotor, we use the rotational term formula:
- Where J is the rotational energy level expressed in terms of quantum numbers J and K.
- H is the rotational constant, which is a characteristic of the molecule. It can be calculated using the moment of inertia and the bond lengths.
- B is another rotational constant that depends on the shape and symmetry of the molecule.
By plugging in the values for the moment of inertia, bond lengths, and other relevant parameters into the formula, you can calculate the rotational terms for a 14NH3 molecule.
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