Answer :
We start with Newton's second law, which states that
[tex]$$ F = m \cdot a, $$[/tex]
where:
- [tex]$F$[/tex] is the force acting on the canoe,
- [tex]$m$[/tex] is the mass of the canoe and paddler combined, and
- [tex]$a$[/tex] is the acceleration produced.
Rearranging the formula to solve for acceleration, we get:
[tex]$$ a = \frac{F}{m}. $$[/tex]
Substitute the given values:
[tex]$$ a = \frac{156 \text{ N}}{220 \text{ kg}}. $$[/tex]
Calculating the value:
[tex]$$ a \approx 0.709 \text{ m/s}^2. $$[/tex]
Rounded to one decimal place, this result is approximately [tex]$0.7 \text{ m/s}^2$[/tex].
Thus, the acceleration of the canoe is [tex]$0.7 \text{ m/s}^2$[/tex], which corresponds to option A.
[tex]$$ F = m \cdot a, $$[/tex]
where:
- [tex]$F$[/tex] is the force acting on the canoe,
- [tex]$m$[/tex] is the mass of the canoe and paddler combined, and
- [tex]$a$[/tex] is the acceleration produced.
Rearranging the formula to solve for acceleration, we get:
[tex]$$ a = \frac{F}{m}. $$[/tex]
Substitute the given values:
[tex]$$ a = \frac{156 \text{ N}}{220 \text{ kg}}. $$[/tex]
Calculating the value:
[tex]$$ a \approx 0.709 \text{ m/s}^2. $$[/tex]
Rounded to one decimal place, this result is approximately [tex]$0.7 \text{ m/s}^2$[/tex].
Thus, the acceleration of the canoe is [tex]$0.7 \text{ m/s}^2$[/tex], which corresponds to option A.
