High School

A 51.7 cm-long pendulum takes 2.50 minutes to undergo 102.3 complete oscillations.

(a) Compute the pendulum's period (in seconds).

(b) Determine the acceleration due to gravity (in m/s²) at the place where the pendulum is located.

Answer :

Final answer:

To compute the period of the pendulum, divide the total time taken for the oscillations by the number of oscillations. The period is given by the equation T = t/N. The acceleration due to gravity can be found using the equation g = 4π^2L / T^2.

Explanation:

To compute the period of the pendulum, divide the total time taken for the oscillations by the number of oscillations. The period is given by the equation T = t/N, where T is the period, t is the total time, and N is the number of oscillations.

In this case, the period is 2.50 minutes divided by 102.3 oscillations, which is approximately 0.024 seconds per oscillation.

The acceleration due to gravity can be found using the equation g = 4π^2L / T^2, where g is the acceleration due to gravity, L is the length of the pendulum, and T is the period.

In this case, the acceleration due to gravity is 4π^2 x 0.517 m / (0.024 s)^2, which is approximately 10.09 m/s^2.

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