High School

If 51.7 mL of silver nitrate solution reacts with excess potassium chloride solution to yield 0.767 g of precipitate, what is the molarity of silver ion in the original solution?

Answer :

Final answer:

To find the molarity of silver ion in the original solution, we can use the formula Molarity (M) = moles of solute / liters of solution.

Explanation:

To find the molarity of silver ion in the original solution, we first need to determine the number of moles of silver nitrate used. The molarity (M) of a solution is defined as moles of solute divided by liters of solution. Given that 0.767 g of precipitate is formed, we can calculate the number of moles of silver nitrate using its molar mass (169.87 g/mol). Then, we can divide this value by the volume of silver nitrate solution used (51.7 mL = 0.0517 L) to find the molarity of silver ion.

Using the formula:

Molarity (M) = moles of solute / liters of solution

We have:

Molarity (M) = (0.767 g / 169.87 g/mol) / 0.0517 L

Simplifying the calculation, we find that the molarity of silver ion in the original solution is approximately 0.228 M.

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