High School

The price of gas in the U.S. rose dramatically in the spring and early summer of 2022, but later in the year began to fall. The price of gas was an issue in the 2022 elections. We obtained data on the average price of regular gas in each of the 50 states and the District of Columbia (\(n = 51\)). The data come from AAA for the week of January 11, 2023.

The stem-and-leaf plot and the sums of squares are given below.

The price of regular gas on January 11, 2023, was $2.921 in Oklahoma. What is the z-score for the price of regular gas in Oklahoma? Remember, the sign for a z-score DOES MATTER in your answer. Use three decimal places in your answer and follow the proper rules of rounding.

Answer :

The z-score for the price of regular gas in Oklahoma would be 0.605.

To find the z-score for the price of regular gas in Oklahoma, we need to use the formula:

z = (x - μ) / σ

Where x is the observed value, μ is the mean, and σ is the standard deviation. In this case, the observed value is 2.921, and we need to calculate the mean and standard deviation using the given data.

Once we have the mean and standard deviation, we can plug in the values into the formula to calculate the z-score.

Example:

If the mean is 2.8 and the standard deviation is 0.2, the calculation would be as follows:

z = (2.921 - 2.8) / 0.2 = 0.605

So, the z-score for the price of regular gas in Oklahoma would be 0.605.

Learn more about the topic of "z-score" here:

https://brainly.com/question/30765368

#SPJ11

The z-score for the price of regular gas in Oklahoma would be 0.605.

To find the z-score for the price of regular gas in Oklahoma, we need to use the formula:

  • z = (x - μ) / σ

Where x is the observed value, μ is the mean, and σ is the standard deviation. In this case, the observed value is 2.921, and we need to calculate the mean and standard deviation using the given data.

  • z = (2.921 - 2.8) / 0.2 = 0.605

Hence, the z-score for the information given is : 0.605.

Learn more on zscore : - https://brainly.com/question/30765368

#SPJ2