Answer :
Final answer:
The molar volume of the gas at 95.2°C and 101.2 kPa is approximately 368.35 liters per mole (L/mol).
Explanation:
To calculate the molar volume of a gas at a specific temperature and pressure, we can use the ideal gas law equation: PV = nRT.
Given:
- Temperature (T) = 95.2°C = 95.2 + 273.15 = 368.35 K
- Pressure (P) = 101.2 kPa
First, we need to convert the pressure to the appropriate units. 1 kPa = 0.001 MPa, so the pressure in megapascals (MPa) is 0.1012 MPa.
Next, we can rearrange the ideal gas law equation to solve for volume (V):
V = (nRT) / P
Since we are calculating the molar volume, we can assume that the number of moles (n) is 1 mole.
Substituting the given values into the equation:
V = (1 mol * 0.1012 MPa * 368.35 K) / (0.1012 MPa)
Simplifying the equation:
V = 368.35 L/mol
Therefore, the molar volume of the gas at 95.2°C and 101.2 kPa is approximately 368.35 liters per mole (L/mol).
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