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When red-headed woodpeckers (Melanerpes erythrocephalus) strike the trunk of a tree, they can experience an acceleration ten times greater than the acceleration of gravity, or about [tex]98.1 \, \text{m/s}^2[/tex]. What is this acceleration in [tex]\text{in/s}^2[/tex]?

Answer :

98.1 m/s² × (1 in)/(0.0254 m) ≈ 3862 in/s²

Final answer:

The acceleration of a red-headed woodpecker striking a tree, given as 98.1 m/s2, is approximately 3863.417 in/s2 when converted using the factor of 1m = 39.37in.

Explanation:

To convert the acceleration of the red-headed woodpecker from meters per second squared (m/s2) to inches per second squared (in/s2), we need to use a conversion factor. One meter is equivalent to approximately 39.37 inches.

So, we can multiply the given acceleration, 98.1 m/s2, by 39.37 to get the equivalent acceleration in in/s2. This gives us an acceleration of approximately 3863.417 in/s2.

Learn more about Unit Conversion here:

https://brainly.com/question/32030244

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