Answer :
Final answer:
The proportion of Puerto Rico high school students in the class of 2019 who had SAT total scores above 1400 is approximately 0.14%. The 90th percentile of the SAT total scores of Puerto Rico high school students in the class of 2019 is approximately 1160.76. The probability that exactly one of the ten random Puerto Rico high school students in the class of 2019 had a SAT total score above 1400 is approximately 1.36%.
Explanation:
To find the proportion of Puerto Rico high school students in the class of 2019 who had SAT total scores above 1400, we need to calculate the z-score and use the standard normal distribution table or a calculator.
Step 1: Calculate the z-score using the formula:
z = (x - mean) / standard deviation
where x is the value we want to find the proportion for.
For x = 1400:
z = (1400 - 944) / 180 = 2.978
Step 2: Use the standard normal distribution table or a calculator to find the proportion corresponding to the z-score.
The proportion of Puerto Rico high school students in the class of 2019 who had SAT total scores above 1400 is approximately 0.0014 or 0.14%.
To find the 90th percentile of the SAT total scores of Puerto Rico high school students in the class of 2019, we can use the z-score formula:
z = invNorm(p)
where p is the desired percentile as a decimal.
For p = 0.9:
z = invNorm(0.9) ≈ 1.282
Step 3: Calculate the score using the formula:
x = mean + (z * standard deviation)
x = 944 + (1.282 * 180) ≈ 1160.76
The 90th percentile of the SAT total scores of Puerto Rico high school students in the class of 2019 is approximately 1160.76.
To find the probability that exactly one of the ten random Puerto Rico high school students in the class of 2019 had a SAT total score above 1400, we can use the binomial distribution formula:
P(X = k) = (n choose k) * p^k * (1 - p)^(n - k)
where n is the number of trials, k is the number of successes, and p is the probability of success.
In this case, n = 10, k = 1, and p = 0.0014 (probability of a student having a score above 1400).
Using the formula:
P(X = 1) = (10 choose 1) * (0.0014)^1 * (1 - 0.0014)^(10 - 1)
P(X = 1) ≈ 0.0136 or 1.36%
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