Answer :
The mass of 2.59 moles of glucose is approximately 466.82 grams and the number of moles in 59.1 grams of sodium nitrate is approximately 0.6946 mol.
(a) To determine the mass of 2.59 moles of glucose (C6H12O6) in grams, we need to use the molar mass of glucose.
The molar mass of glucose is calculated by adding up the atomic masses of all the atoms in one molecule of glucose.
C6H12O6 consists of 6 carbon (C) atoms, 12 hydrogen (H) atoms, and 6 oxygen (O) atoms.
The atomic masses of carbon, hydrogen, and oxygen are approximately 12.01 g/mol, 1.01 g/mol, and 16.00 g/mol, respectively.
Therefore, the molar mass of glucose can be calculated as follows:
Molar mass of C6H12O6 = (6 * atomic mass of C) + (12 * atomic mass of H) + (6 * atomic mass of O)
= (6 * 12.01 g/mol) + (12 * 1.01 g/mol) + (6 * 16.00 g/mol)
= 72.06 g/mol + 12.12 g/mol + 96.00 g/mol
= 180.18 g/mol
Now, we can calculate the mass of 2.59 moles of glucose using the molar mass:
Mass of glucose = Number of moles * Molar mass
= 2.59 mol * 180.18 g/mol
= 466.8162 g
(b) To determine the number of moles in 59.1 grams of sodium nitrate (NaNO3), we need to use the molar mass of NaNO3.
The molar mass of sodium nitrate can be calculated by adding up the atomic masses of all the atoms in one molecule of NaNO3.
NaNO3 consists of 1 sodium (Na) atom, 1 nitrogen (N) atom, and 3 oxygen (O) atoms.
The atomic masses of sodium, nitrogen, and oxygen are approximately 22.99 g/mol, 14.01 g/mol, and 16.00 g/mol, respectively.
Therefore, the molar mass of sodium nitrate can be calculated as follows:
Molar mass of NaNO3 = atomic mass of Na + atomic mass of N + (3 * atomic mass of O)
= 22.99 g/mol + 14.01 g/mol + (3 * 16.00 g/mol)
= 22.99 g/mol + 14.01 g/mol + 48.00 g/mol
= 85.00 g/mol
Now, we can calculate the number of moles in 59.1 grams of sodium nitrate using the molar mass:
Number of moles = Mass of NaNO3 / Molar mass
= 59.1 g / 85.00 g/mol
= 0.6946 mol
To learn more about glucose click here:
https://brainly.com/question/397060#
#SPJ11
