Answer :
To calculate the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters). In this case, you are given 173 grams of sucrose and a volume of 1.70 liters. molarity of the sucrose solution is 0.297 M.
First, we need to convert the mass of sucrose to moles. The molar mass of sucrose can be calculated by adding up the atomic masses of all the atoms in the compound. sucrose : (12.01 g/mol x 12) + (1.01 g/mol x 22) + (16.00 g/mol x 11) = 342.34 g/mol
To convert grams to moles, divide the given mass by the molar mass:
173 g / 342.34 g/mol = 0.505 mo Next, divide the number of moles by the volume of the solution in liters to obtain the molarity 0.505 mol / 1.70 L = 0.297 M
Therefore, the molarity of the sucrose solution is 0.297 M. It's important to note that the molarity represents the concentration of the solute in the solution. In this case, the molarity indicates the number of moles of sucrose dissolved in 1 liter of solution.
The formula represents the chemical composition of sucrose, where C stands for carbon, H stands for hydrogen, and O stands for oxygen. The subscript numbers represent the number of atoms for each element in the molecule
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