Answer :
The correct answer is: 2.24 moles of carbon dioxide gas are produced when 224 g of calcium carbonate decomposes.
- To determine the number of moles of carbon dioxide (CO2) gas produced when 224 g of calcium carbonate (CaCO3) decomposes, we need to use the molar mass of calcium carbonate and the stoichiometry of the balanced chemical equation.
- The balanced equation for the decomposition of calcium carbonate is:CaCO3 -> CaO + CO2The molar mass of calcium carbonate (CaCO3) is calculated by adding the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms:
- Molar mass of CaCO3 = 40.08 g/mol (Ca) + 12.01 g/mol (C) + (3 * 16.00 g/mol) (O) = 100.09 g/molNow, we can calculate the number of moles of carbon dioxide produced using the given mass of calcium carbonate:
- Number of moles of CO2 = (Mass of CaCO3 / Molar mass of CaCO3)
= 224 g / 100.09 g/mol
≈ 2.24 moles of CO2
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