Answer :
The stress in a concrete cylinder with a diameter of 6 inches and subjected to a compressive force of 122,700 pounds is approximately 4,812.5 pounds per square inch (psi).
Stress is defined as the force applied per unit area of a material. To calculate stress, we divide the applied force by the cross-sectional area of the object.
For the steel rod, the applied tension force is 120,000 pounds, and the cross-sectional area is 2.4 square inches. Therefore, the stress can be calculated as:
Stress = Tension Force / Cross-sectional Area
= 120,000 pounds / 2.4 square inches
= 50,000 psi
Hence, the stress in the steel rod is 50,000 pounds per square inch.
For the concrete cylinder, the compressive force is 122,700 pounds, and the cross-sectional area can be calculated using the formula for the area of a circle:
Cross-sectional Area = π * (radius)^2
= π * (3 inches)^2
= π * 9 square inches
≈ 28.27 square inches
Therefore, the stress in the concrete cylinder can be calculated as:
Stress = Compressive Force / Cross-sectional Area
= 122,700 pounds / 28.27 square inches
≈ 4,812.5 psi
Thus, the stress in the concrete cylinder is approximately 4,812.5 pounds per square inch.
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