Answer :
In the RISC-V instruction add x8, x8, x20, x8 is being added with x20 and the result is stored in x8. The machine code for this instruction can be obtained by converting the instruction into binary format, which comprises of 32-bits. The first 7 bits are the opcode which corresponds to the instruction and the next three groups of 5 bits are the register numbers for the source register, the source register, and the destination register.
Let's convert this instruction into machine code (binary and hex):
RISC-V instruction: add x8, x8, x20.
Binary: 0000000 00101 01000 000 00000 0110011 Hex: 0x00842833.
The machine code obtained for this instruction is 00000000010101000000000000110011 in binary and 0x00842833 in hex.
The first 7 bits are all zeros, which indicates that this is an R-type instruction. The next three groups of 5 bits correspond to the source register, the source register, and the destination register.
In this case, the source registers are x8 and x20, and the destination register is x8. The opcode for the add instruction is 0110011, which is represented in binary by the last 7 bits of the instruction.
Thus, the machine code for this instruction is 00000000010101000000000000110011 (binary) and 0x00842833 (hex).In conclusion, the RISC-V instruction add x8, x8, x20 can be converted into machine code by converting the instruction into binary format.
The machine code obtained for this instruction is 00000000010101000000000000110011 in binary and 0x00842833 in hex.
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