Answer :
To solve the problem, we can follow these steps:
1. Multiply the numerical coefficients:
[tex]$$4 \times (-3) \times (-7) = 84$$[/tex]
2. Add the exponents of [tex]$x$[/tex] from each term. Since the first term is [tex]$4x$[/tex], it has an exponent of [tex]$1$[/tex]. The second term [tex]$-3x^8$[/tex] has an exponent of [tex]$8$[/tex], and the third term [tex]$-7x^3$[/tex] has an exponent of [tex]$3$[/tex]. Adding these exponents gives:
[tex]$$1 + 8 + 3 = 12$$[/tex]
3. Combine the product of the coefficients with the sum of the exponents on [tex]$x$[/tex] to get the final product:
[tex]$$84x^{12}$$[/tex]
Thus, the product is
[tex]$$84x^{12}.$$[/tex]
1. Multiply the numerical coefficients:
[tex]$$4 \times (-3) \times (-7) = 84$$[/tex]
2. Add the exponents of [tex]$x$[/tex] from each term. Since the first term is [tex]$4x$[/tex], it has an exponent of [tex]$1$[/tex]. The second term [tex]$-3x^8$[/tex] has an exponent of [tex]$8$[/tex], and the third term [tex]$-7x^3$[/tex] has an exponent of [tex]$3$[/tex]. Adding these exponents gives:
[tex]$$1 + 8 + 3 = 12$$[/tex]
3. Combine the product of the coefficients with the sum of the exponents on [tex]$x$[/tex] to get the final product:
[tex]$$84x^{12}$$[/tex]
Thus, the product is
[tex]$$84x^{12}.$$[/tex]