High School

Assume that the population mean is to be estimated from the sample described. Use the sample results to approximate the margin of error and the 95% confidence interval.

Sample details:
- Sample size, \( n = 49 \)
- Sample mean, \( \bar{x} = 51.7 \) seconds
- Sample standard deviation, \( s = 6.2 \) seconds

Answer :

Therefore, the 95% confidence interval for the population mean is approximately 49.969 seconds to 53.431 seconds.

To estimate the population mean, the margin of error can be approximated as the critical value (Z*) multiplied by the standard error (s/√(n)). For a 95% confidence level, Z* is approximately 1.96.

Using the given sample results:

n = 49

x = 51.7 seconds (sample mean)

s = 6.2 seconds (sample standard deviation)

The standard error (SE) is calculated as s/√(n):

SE = 6.2 / √(49)

≈ 0.883 seconds

The margin of error (ME) is then calculated as Z * SE:

ME = 1.96 * 0.883

≈ 1.731 seconds

The 95% confidence interval is calculated by subtracting and adding the margin of error to the sample mean:

95% Confidence Interval = (x - ME, x + ME)

= (51.7 - 1.731, 51.7 + 1.731)

= (49.969, 53.431)

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