Answer :
The mass of potassium chloride (KCI) that will be formed if 36.2 g of potassium bromide (KBr) react with excess chlorine is 22.7 g
How do i determine the mass of potassium chloride (KCI) formed?
The mass of potassium chloride (KCI) that will be formed from the reaction can be obtain as illustrated below:
2KBr + Cl₂ -> 2KCl + 2Br₂
- Molar mass of KBr = 119 g/mol
- Mass of KBr from the balanced equation = 2 × 119 = 238 g
- Molar mass of KCl = 74.5 g/mol
- Mass of KCl from the balanced equation = 2 × 74.5 = 149 g
From the balanced equation above,
238 g of KBr reacted to produce 149 g of KCl
Therefore,
36.2 g of KBr will react to produce = (36.2 g × 149 g) / 238 g = 22.7 g of KCl
Thus, we can conclude from the above equation that the mass of potassium chloride (KCI) forned is 22.7 g
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