Answer :
Answer:
7.667 m/s²
Explanation:
The acceleration can be calculated as
[tex]a=\frac{v_f-v_i}{t}[/tex]Where vf is the final velocity, vi is the initial velocity and t is the time. Replacing vf = 0 m/s, vi = 39.1 m/s, and t = 5.1 s, we get:
[tex]a=\frac{0\text{ m/s - 39.1 m/s}}{5.1\text{ s}}=-7.667\text{ m/s}^2[/tex]Therefore, the magnitude of the acceleration is 7.667 m/s²