College

A 20 N force to the right and a 5.0 N force to the left are simultaneously applied to an 8.0 kg object. What is the net force on the object?

A. 100 N, right
B. 122 N, left
C. 25 N, left
D. 15 N, right

Answer :

Answer:

d. J. 15 N, right

Explanation:

let the force to the right be positive, and the left be negative

Step one:

given

20N force right

5N force left.

The net force is equal to the summation of all the forces in Newton

Net force= +20-5

Net force=+15N

The direction is right.

Final answer:

The net force acting on the object is calculated by considering the direction of the forces. The result after subtracting the 5.0 N force from the 20 N force, due to opposing directions, is 15 N directed to the right.

Explanation:

To determine the net force on an object, we must consider the direction of the forces, as force is a vector quantity. Here, we have one force moving to the right (20 N) and one moving to the left (5.0 N). We subtract them, taking into account their directions, to find the net force. So, the net force is 20 N (right) - 5.0 N (left) = 15 N (right). Hence, the answer is d. J. 15 N, right.

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