High School

A 20-kg crate hangs at the end of a long rope. Find its acceleration (magnitude and direction) when the tension in the rope is:

a. 250 N
b. 150 N
c. 156 N
d. 196 N

Answer :

2.69ms2, −2.31ms2, −9.81ms2 and 0ms2 are acceleration (magnitude and direction) when the tension in the rope is 250 N, 150 N, 156 N and 196N respectively.

What is acceleration?

Acceleration is the rate at which an object changes its velocity over time. It is a vector quantity, which means it has both magnitude (speed) and direction. The most common unit of acceleration is meters per second squared (m/s²).

As, ΣFy=may

Using the assumption that positive means up and negative means down, we obtain:

T−mg=may

a) when T=+250:

250−(20)(9.81)=(20) ay

ay=2.69ms2

Provide the direction to your calculator. As my response was affirmative, there is an upward acceleration.

b) when T=+150:

150−(20)(9.81)=(20)ay

ay=−2.31ms2

or

ay=2.31ms2

As my solution was negative.

c) when T=0:

0−(20)(9.81)=(20)ay

ay=−9.81ms2

or

ay=9.81ms2

As my solution was negative.

d) when T=+196:

196−(20)(9.81)=(20)ay

ay=0ms2

Keep in mind that the tension and weight are equivalent while the box is not accelerating.

To learn more about acceleration visit;

https://brainly.com/question/30660316

#SPJ4