Answer :
a. The acceleration of the train is 0.4 m/s²
From the question, we have the following given data:
- Mass of train (m) = [tex]7.5\times10^5\ Kg[/tex]
- Initial speed of train (u) = 0 m/s
- Final speed of train (v) = 24 m/s
- Time taken (t) = 60 s
- Acceleration of train (a) =?
With the given information, we can calculate the acceleration of the train using one of the equations of motion as illustrated below:
v = u + at
24 = 0 + (a × 60)
24 = 0 + 60a
24 = 60a
Divide both sides by 60
a = 24 / 60
a = 0.4 m/s²
Thus, the acceleration is 0.4 m/s²
Answer:
0.4
Explanation:
So we are given the situation that the final speed of the train, It's 24 m/s. Initially it was addressed. That means you're exposed, And it takes 60 seconds for the train to reach. We all know that exploration is a consumer Change in velocity. That means 24 0, divided by 60 16. So in terms of in terms of magnitude, let's find out this value. That means we need to find 24 60, and the answer is 0.4. The isolation of the plan is 0.4 m apart. So I hope you understood this concept. Thank you very much.
