Answer :
The specific gravity of the reservoir gas is approximately 0.698.The gas gravity (Gg) is defined as the ratio of the density of the gas to the density of air at standard conditions.
To calculate the specific gravity of the reservoir gas, we can use the provided information and apply the gas gravity equation.
Given:
Gas production rate = 47,780 scf/STB
Separator temperature = 78°F
Separator pressure = 500 psig
Separator gas specific gravity = 0.698
Stock-tank liquid gravity = 59.1 API
1. Convert the separator pressure to absolute pressure:
Absolute pressure = Separator pressure + atmospheric pressure
Atmospheric pressure is typically around 14.7 psi.
Absolute pressure = 500 psig + 14.7 psi ≈ 514.7 psia
2. Convert the separator temperature to absolute temperature:
Absolute temperature (°R) = Rankine temperature scale
Absolute temperature (°R) = (78°F + 459.67)
3. Calculate the density of air at standard conditions:
The density of air at standard conditions can be taken as 0.0765 lb/ft³.
4. Calculate the density of the gas at separator conditions:
Density of gas = Separator gas specific gravity * Density of air at standard conditions
5. Calculate the specific gravity of the reservoir gas:
The specific gravity of the reservoir gas can be calculated by dividing the density of the gas by the density of air at standard conditions.
Specific gravity of reservoir gas = Density of gas / Density of air at standard conditions
Now, let's perform the calculations:
1. Convert temperature to Rankine scale:
Temperature (°R) = 78°F + 459.67 ≈ 537.67 °R
2. Calculate the density of air at standard conditions:
Density of air at standard conditions = 0.0765 lb/ft³
3. Calculate the density of the gas at separator conditions:
Density of gas = Separator gas specific gravity * Density of air at standard conditions
Density of gas = 0.698 * 0.0765 lb/ft³
4. Calculate the data specific gravity of the reservoir gas:
Specific gravity of reservoir gas = Density of gas / Density of air at standard conditions
Specific gravity of reservoir gas = (0.698 * 0.0765 lb/ft³) / 0.0765 lb/ft³
Therefore, the specific gravity of the reservoir gas is approximately 0.698.
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