Middle School

The means and mean absolute deviations of the individual times of members on two 4x400-meter relay track teams are shown in the table below:

| Team | Mean | Mean Absolute Deviation |
|------|------|--------------------------|
| A | 59.32 s | 1.5 s |
| B | 59.1 s | 2.45 s |

What percent of Team B's mean absolute deviation is the difference in the means?

A. 9%
B. 15%
C. 25%
D. 65%

Answer :

Answer:

A

Step-by-step explanation:

Answer:

9%

Step-by-step explanation:

To find the percentage of Team B's mean absolute deviation difference in the means, you have to subtract the two means, 59.32-59.1.

After this, divide your answer the the mean absolute deviation of Team B, or you could put it all in the calculator or paper like this:

[tex]\frac{59.32-59.1}{2.4}[/tex]

You'd then end with the decimal: .0916, which you would multiply by 100 to get about 9%

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