High School

What is the sum of the geometric sequence [tex]-4, 24, -144, \ldots[/tex] if there are 6 terms?

A. 26,660
B. [tex]-159,963[/tex]
C. 159,963
D. 26,661

Answer :

We are given a geometric sequence with the first term
[tex]$$a=-4,$$[/tex]
common ratio
[tex]$$r=-6,$$[/tex]
and the number of terms
[tex]$$n=6.$$[/tex]

The sum of the first [tex]$n$[/tex] terms of a geometric sequence is given by
[tex]$$
S_n = a \times \frac{r^n - 1}{r - 1}.
$$[/tex]

Step 1. Compute [tex]$r^n$[/tex]:

We calculate
[tex]$$
r^6 = (-6)^6.
$$[/tex]
Since an even power of a negative number is positive, we have
[tex]$$
(-6)^6 = 46656.
$$[/tex]

Step 2. Compute the numerator of the formula:

Subtract 1 from [tex]$r^6$[/tex]:
[tex]$$
r^6 - 1 = 46656 - 1 = 46655.
$$[/tex]

Step 3. Compute the denominator of the formula:

Subtract 1 from [tex]$r$[/tex]:
[tex]$$
r - 1 = -6 - 1 = -7.
$$[/tex]

Step 4. Substitute into the sum formula:

Now replace [tex]$a$[/tex], the numerator, and the denominator in the formula:
[tex]$$
S_6 = -4 \times \frac{46655}{-7}.
$$[/tex]

The negatives cancel out:
[tex]$$
S_6 = \frac{-4 \times 46655}{-7} = 4 \times \frac{46655}{7}.
$$[/tex]

Step 5. Simplify to obtain the final sum:

Multiplying and dividing gives
[tex]$$
S_6 = 26660.
$$[/tex]

Thus, the sum of the geometric sequence with 6 terms is
[tex]$$\boxed{26660}.$$[/tex]