Answer :
We start by noting that the given number of atoms is equal to Avogadro's number, which is
[tex]$$6.02 \times 10^{23}.$$[/tex]
This means that there is exactly one mole of potassium. Since one mole of potassium weighs its atomic mass, we have:
[tex]$$\text{Mass} = 39.1 \text{ grams.}$$[/tex]
Thus, the mass of [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium is [tex]$\boxed{39.1 \text{ g}}$[/tex].
[tex]$$6.02 \times 10^{23}.$$[/tex]
This means that there is exactly one mole of potassium. Since one mole of potassium weighs its atomic mass, we have:
[tex]$$\text{Mass} = 39.1 \text{ grams.}$$[/tex]
Thus, the mass of [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium is [tex]$\boxed{39.1 \text{ g}}$[/tex].
