Answer :
First, we start by arranging the data in increasing order. The given data set is
[tex]$$204,\;216,\;111,\;224,\;230,\;211,\;210,\;198,\;200,\;218.$$[/tex]
When sorted, the data becomes
[tex]$$111,\;198,\;200,\;204,\;210,\;211,\;216,\;218,\;224,\;230.$$[/tex]
Step 1. Calculate the Range
The range is defined as the difference between the maximum and minimum values. Here, the minimum value is [tex]$111$[/tex] and the maximum value is [tex]$230$[/tex]. Thus,
[tex]$$\text{Range} = 230 - 111 = 119.$$[/tex]
Step 2. Determine the Lower Quartile [tex]\((Q_1)\)[/tex]
Since there are [tex]$10$[/tex] numbers, we divide the data set into two halves of [tex]$5$[/tex] numbers each to determine the quartiles.
The lower half of the data is:
[tex]$$111,\;198,\;200,\;204,\;210.$$[/tex]
The median of this lower half is the third number (since there are [tex]$5$[/tex] numbers), which is
[tex]$$Q_1 = 200.$$[/tex]
Step 3. Determine the Upper Quartile [tex]\((Q_3)\)[/tex]
The upper half of the data is:
[tex]$$211,\;216,\;218,\;224,\;230.$$[/tex]
The median of this upper half is the third number, which is
[tex]$$Q_3 = 218.$$[/tex]
Final Answer:
- Range: [tex]$119$[/tex]
- Lower Quartile: [tex]$200$[/tex]
- Upper Quartile: [tex]$218$[/tex]
[tex]$$204,\;216,\;111,\;224,\;230,\;211,\;210,\;198,\;200,\;218.$$[/tex]
When sorted, the data becomes
[tex]$$111,\;198,\;200,\;204,\;210,\;211,\;216,\;218,\;224,\;230.$$[/tex]
Step 1. Calculate the Range
The range is defined as the difference between the maximum and minimum values. Here, the minimum value is [tex]$111$[/tex] and the maximum value is [tex]$230$[/tex]. Thus,
[tex]$$\text{Range} = 230 - 111 = 119.$$[/tex]
Step 2. Determine the Lower Quartile [tex]\((Q_1)\)[/tex]
Since there are [tex]$10$[/tex] numbers, we divide the data set into two halves of [tex]$5$[/tex] numbers each to determine the quartiles.
The lower half of the data is:
[tex]$$111,\;198,\;200,\;204,\;210.$$[/tex]
The median of this lower half is the third number (since there are [tex]$5$[/tex] numbers), which is
[tex]$$Q_1 = 200.$$[/tex]
Step 3. Determine the Upper Quartile [tex]\((Q_3)\)[/tex]
The upper half of the data is:
[tex]$$211,\;216,\;218,\;224,\;230.$$[/tex]
The median of this upper half is the third number, which is
[tex]$$Q_3 = 218.$$[/tex]
Final Answer:
- Range: [tex]$119$[/tex]
- Lower Quartile: [tex]$200$[/tex]
- Upper Quartile: [tex]$218$[/tex]