Answer :
To find the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, we need to understand that [tex]\(6.02 \times 10^{23}\)[/tex] is known as Avogadro's number, which represents one mole of any substance.
1. The atomic mass of potassium is given as 39.1. This is the mass of one mole of potassium atoms, expressed in grams per mole (g/mol).
2. Since [tex]\(6.02 \times 10^{23}\)[/tex] atoms is precisely one mole, the mass of these atoms will be the same as the atomic mass in grams.
3. Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] potassium atoms is 39.1 grams.
Thus, the correct answer is:
B. [tex]\(39.1 \, \text{g}\)[/tex]
1. The atomic mass of potassium is given as 39.1. This is the mass of one mole of potassium atoms, expressed in grams per mole (g/mol).
2. Since [tex]\(6.02 \times 10^{23}\)[/tex] atoms is precisely one mole, the mass of these atoms will be the same as the atomic mass in grams.
3. Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] potassium atoms is 39.1 grams.
Thus, the correct answer is:
B. [tex]\(39.1 \, \text{g}\)[/tex]
