College

Maria ran an experiment to determine the optimal conditions for growing artichokes. The data below displays the weights of the artichokes she grew (measured in grams).

\[
\begin{array}{lllll}
78.8 & 97.4 & 54.2 & 75.6 & 65.7 \\
97.4 & 83.9 & 65.4 & 97.4 & 72.7
\end{array}
\]

1. What is the mean weight of the artichokes?
Mean = [tex]$\square$[/tex]

2. What is the median weight of the artichokes?
Median = [tex]$\square$[/tex]

3. What is the mode weight of the artichokes?
Mode = [tex]$\square$[/tex]

Answer :

Sure! Let's find the mean, median, and mode weights of the artichokes Maria grew.

### Mean

To find the mean (average) weight, we add all the weights together and then divide by the number of weights.

List of artichoke weights:
[tex]\[ 78.8, 97.4, 54.2, 75.6, 65.7, 97.4, 83.9, 65.4, 97.4, 72.7 \][/tex]

1. Add all the weights:
[tex]\[ 78.8 + 97.4 + 54.2 + 75.6 + 65.7 + 97.4 + 83.9 + 65.4 + 97.4 + 72.7 = 788.5 \][/tex]

2. Divide by the number of weights (10 in this case):
[tex]\[ \frac{788.5}{10} = 78.85 \][/tex]

So, the mean weight of the artichokes is 78.85 grams.

### Median

To find the median, we need to arrange the weights in order and find the middle value.

1. Arrange the weights in ascending order:
[tex]\[ 54.2, 65.4, 65.7, 72.7, 75.6, 78.8, 83.9, 97.4, 97.4, 97.4 \][/tex]

2. Since there are 10 weights (an even number), the median is the average of the 5th and 6th values:
[tex]\[ \text{5th value: } 75.6, \quad \text{6th value: } 78.8 \][/tex]

3. Calculate the average of these two values:
[tex]\[ \frac{75.6 + 78.8}{2} = 77.2 \][/tex]

So, the median weight of the artichokes is 77.2 grams.

### Mode

The mode is the weight that appears most frequently.

1. Count the frequency of each weight:
[tex]\[ 78.8, 97.4, 54.2, 75.6, 65.7, 97.4, 83.9, 65.4, 97.4, 72.7 \][/tex]

2. Identify the number that appears most frequently. Here, 97.4 appears 3 times.

Thus, the mode weight of the artichokes is 97.4 grams.

To summarize:

- Mean: 78.85 grams
- Median: 77.2 grams
- Mode: 97.4 grams