Answer :
To find the approximate stopping distance for a car traveling at 35 mph on a wet road, we use the formula provided:
[tex]\[ d(v) = \frac{2.15 \times v^2}{64.4 \times f} \][/tex]
Here, [tex]\( v \)[/tex] is the velocity of the car in miles per hour (mph), and [tex]\( f \)[/tex] is the friction factor. In the absence of a specific friction factor, we’ll assume [tex]\( f = 1 \)[/tex].
Steps to solve the problem:
1. Identify the given information:
- The velocity ([tex]\( v \)[/tex]) of the car is 35 mph.
2. Substitute the values into the formula:
- Plug in the value of [tex]\( v = 35 \)[/tex] mph.
- Use [tex]\( f = 1 \)[/tex] for simplicity since the friction factor is not provided.
3. Calculate the stopping distance:
- First, calculate [tex]\( v^2 = 35^2 = 1225 \)[/tex].
- Next, substitute these values into the formula:
[tex]\[ d(35) = \frac{2.15 \times 1225}{64.4 \times 1} \][/tex]
- Simplify the multiplication: [tex]\( 2.15 \times 1225 = 2633.75 \)[/tex].
- Then divide by 64.4:
[tex]\[ d(35) = \frac{2633.75}{64.4} \approx 40.90 \text{ ft} \][/tex]
So, the approximate stopping distance for a car traveling at 35 mph on a wet road is about 40.9 feet.
[tex]\[ d(v) = \frac{2.15 \times v^2}{64.4 \times f} \][/tex]
Here, [tex]\( v \)[/tex] is the velocity of the car in miles per hour (mph), and [tex]\( f \)[/tex] is the friction factor. In the absence of a specific friction factor, we’ll assume [tex]\( f = 1 \)[/tex].
Steps to solve the problem:
1. Identify the given information:
- The velocity ([tex]\( v \)[/tex]) of the car is 35 mph.
2. Substitute the values into the formula:
- Plug in the value of [tex]\( v = 35 \)[/tex] mph.
- Use [tex]\( f = 1 \)[/tex] for simplicity since the friction factor is not provided.
3. Calculate the stopping distance:
- First, calculate [tex]\( v^2 = 35^2 = 1225 \)[/tex].
- Next, substitute these values into the formula:
[tex]\[ d(35) = \frac{2.15 \times 1225}{64.4 \times 1} \][/tex]
- Simplify the multiplication: [tex]\( 2.15 \times 1225 = 2633.75 \)[/tex].
- Then divide by 64.4:
[tex]\[ d(35) = \frac{2633.75}{64.4} \approx 40.90 \text{ ft} \][/tex]
So, the approximate stopping distance for a car traveling at 35 mph on a wet road is about 40.9 feet.
