Answer :
To solve this problem, we need to determine which of the given equations allows the variable [tex]\( f \)[/tex] to have both values -7 and 7. Let's examine each option:
Option A: [tex]\( P = 343 \)[/tex]
- This equation only mentions [tex]\( P \)[/tex] and does not involve the variable [tex]\( f \)[/tex]. Therefore, it cannot include both -7 and 7 as values for [tex]\( f \)[/tex].
Option B: [tex]\( f = 49 \)[/tex]
- This equation directly defines [tex]\( f \)[/tex] as 49. There is no room for [tex]\( f \)[/tex] to be -7 or 7 because it's fixed at 49.
Option C: [tex]\( f = 14 \)[/tex]
- Similarly, this equation directly sets [tex]\( f \)[/tex] to be 14. Therefore, [tex]\( f \)[/tex] cannot be -7 or 7.
Option D: [tex]\( t = 21 \)[/tex]
- Like option A, this equation does not involve [tex]\( f \)[/tex]. It only mentions [tex]\( t \)[/tex], so it cannot define [tex]\( f \)[/tex] as -7 or 7.
After examining all the given options, none of them allows [tex]\( f \)[/tex] to have the values -7 and 7. Therefore, none of the options provided are correct regarding [tex]\( f \)[/tex] having these values.
Option A: [tex]\( P = 343 \)[/tex]
- This equation only mentions [tex]\( P \)[/tex] and does not involve the variable [tex]\( f \)[/tex]. Therefore, it cannot include both -7 and 7 as values for [tex]\( f \)[/tex].
Option B: [tex]\( f = 49 \)[/tex]
- This equation directly defines [tex]\( f \)[/tex] as 49. There is no room for [tex]\( f \)[/tex] to be -7 or 7 because it's fixed at 49.
Option C: [tex]\( f = 14 \)[/tex]
- Similarly, this equation directly sets [tex]\( f \)[/tex] to be 14. Therefore, [tex]\( f \)[/tex] cannot be -7 or 7.
Option D: [tex]\( t = 21 \)[/tex]
- Like option A, this equation does not involve [tex]\( f \)[/tex]. It only mentions [tex]\( t \)[/tex], so it cannot define [tex]\( f \)[/tex] as -7 or 7.
After examining all the given options, none of them allows [tex]\( f \)[/tex] to have the values -7 and 7. Therefore, none of the options provided are correct regarding [tex]\( f \)[/tex] having these values.