The means and mean absolute deviations of the individual times of members on two [tex]4 \times 400[/tex]-meter relay track teams are shown in the table below.

[tex]
\begin{array}{|c|c|c|}
\hline
& \text{Team A} & \text{Team B} \\
\hline
\text{Mean} & 59.32 \, \text{s} & 59.1 \, \text{s} \\
\hline
\text{Mean Absolute Deviation} & 0.25 \, \text{s} & 0.15 \, \text{s} \\
\hline
\end{array}
[/tex]

What is the ratio of the difference in the means of the two teams to the mean absolute deviation of Team B?

A. 0.09
B. 0.15
C. 0.25
D. 0.65

To solve this problem, we need to find the ratio of the difference in the means of the two teams to the mean absolute deviation (MAD) of Team B. Here's a step-by-step breakdown:

1. Identify the Means of Each Team:

- The mean time for Team A is 59.32 seconds.
- The mean time for Team B is 59.1 seconds.

2. Calculate the Difference in Means:

Subtract the mean of Team B from the mean of Team A to find the difference in the means:

[tex]\[
\text{Difference in means} = \text{Mean of Team A} - \text{Mean of Team B} = 59.32 - 59.1 = 0.22
\][/tex]

3. Identify the Mean Absolute Deviation of Team B:

The mean absolute deviation for Team B is given as 0.65 seconds.

4. Calculate the Ratio:

To find the ratio, divide the difference in means by the mean absolute deviation of Team B:

[tex]\[
\text{Ratio} = \frac{\text{Difference in means}}{\text{Mean Absolute Deviation of Team B}} = \frac{0.22}{0.65}
\][/tex]

5. Calculate the Result:

By performing the division:

[tex]\[
\text{Ratio} \approx 0.34
\][/tex]

6. Compare the Result with Given Options:

The option closest to 0.34 is 0.65.

Therefore, the correct option is 0.65.