High School

Find the first term of the arithmetic sequence in which [tex]$a_{61} = 293$[/tex] and the common difference is [tex]-3.5[/tex].

A. 503
B. 83
C. [tex]-210[/tex]
D. [tex]-83[/tex]

Answer :

To find the first term of the arithmetic sequence, we can use the formula for the n-th term of an arithmetic sequence:

[tex]\[ a_n = a_1 + (n - 1) \cdot d \][/tex]

Where:
- [tex]\( a_n \)[/tex] is the n-th term of the sequence.
- [tex]\( a_1 \)[/tex] is the first term.
- [tex]\( d \)[/tex] is the common difference.
- [tex]\( n \)[/tex] is the position of the term in the sequence.

In this problem:
- We know [tex]\( a_{61} = 293 \)[/tex], which is the 61st term.
- The common difference [tex]\( d = -3.5 \)[/tex].
- We need to find [tex]\( a_1 \)[/tex].

Let's rearrange the formula to solve for [tex]\( a_1 \)[/tex]:

[tex]\[ a_1 = a_n - (n - 1) \cdot d \][/tex]

Substitute the known values into the formula:

[tex]\[ a_1 = 293 - (61 - 1) \cdot (-3.5) \][/tex]

Calculate the expression inside the parentheses:

[tex]\[ a_1 = 293 - 60 \cdot (-3.5) \][/tex]

Now, calculate [tex]\( 60 \cdot (-3.5) \)[/tex]:

[tex]\[ 60 \cdot (-3.5) = -210 \][/tex]

Substitute back into the equation:

[tex]\[ a_1 = 293 - (-210) \][/tex]

This becomes:

[tex]\[ a_1 = 293 + 210 \][/tex]

Finally, add them together:

[tex]\[ a_1 = 503 \][/tex]

Thus, the first term of the arithmetic sequence is [tex]\( 503 \)[/tex].

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