College

Convert the following temperatures to Celsius:

6) [tex]$32^{\circ} F$[/tex]

7) [tex]$45^{\circ} F$[/tex]

8) [tex]$70^{\circ} F$[/tex]

9) [tex]$80^{\circ} F$[/tex]

10) [tex]$90^{\circ} F$[/tex]

11) [tex]$212^{\circ} F$[/tex]

Answer :

Sure! Let's convert each of the given temperatures from Fahrenheit to Celsius. We will use the conversion formula:

[tex]\[ C = (F - 32) \times \frac{5}{9} \][/tex]

Here's how it works for each temperature:

6) Convert [tex]$32^{\circ} F$[/tex] to Celsius:

Apply the formula:

[tex]\[ C = (32 - 32) \times \frac{5}{9} = 0 \times \frac{5}{9} = 0.0^{\circ} C \][/tex]

7) Convert [tex]$45^{\circ} F$[/tex] to Celsius:

Apply the formula:

[tex]\[ C = (45 - 32) \times \frac{5}{9} = 13 \times \frac{5}{9} = 7.222... \][/tex]

Rounded, that's approximately [tex]\( 7.22^{\circ} C \)[/tex].

8) Convert [tex]$70^{\circ} F$[/tex] to Celsius:

Apply the formula:

[tex]\[ C = (70 - 32) \times \frac{5}{9} = 38 \times \frac{5}{9} = 21.111... \][/tex]

Rounded, that's approximately [tex]\( 21.11^{\circ} C \)[/tex].

9) Convert [tex]$80^{\circ} F$[/tex] to Celsius:

Apply the formula:

[tex]\[ C = (80 - 32) \times \frac{5}{9} = 48 \times \frac{5}{9} = 26.666... \][/tex]

Rounded, that's approximately [tex]\( 26.67^{\circ} C \)[/tex].

10) Convert [tex]$90^{\circ} F$[/tex] to Celsius:

Apply the formula:

[tex]\[ C = (90 - 32) \times \frac{5}{9} = 58 \times \frac{5}{9} = 32.222... \][/tex]

Rounded, that's approximately [tex]\( 32.22^{\circ} C \)[/tex].

11) Convert [tex]$212^{\circ} F$[/tex] to Celsius:

Apply the formula:

[tex]\[ C = (212 - 32) \times \frac{5}{9} = 180 \times \frac{5}{9} = 100.0^{\circ} C \][/tex]

So here are the conversions:

- [tex]\( 32^{\circ} F = 0.0^{\circ} C \)[/tex]
- [tex]\( 45^{\circ} F \approx 7.22^{\circ} C \)[/tex]
- [tex]\( 70^{\circ} F \approx 21.11^{\circ} C \)[/tex]
- [tex]\( 80^{\circ} F \approx 26.67^{\circ} C \)[/tex]
- [tex]\( 90^{\circ} F \approx 32.22^{\circ} C \)[/tex]
- [tex]\( 212^{\circ} F = 100.0^{\circ} C \)[/tex]

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