High School

If [tex]$f(3) = 191.5$[/tex] when [tex]$r = 0.03$[/tex] for the function [tex]$f(t) = \rho e^t$[/tex], then what is the approximate value of [tex]$\rho$[/tex]?

A. 210
B. 175
C. 78
D. 471

Answer :

To solve the problem, we are given the function [tex]\( f(t) = \rho e^t \)[/tex] and specific values for it:

1. [tex]\( f(3) = 191.5 \)[/tex]
2. [tex]\( r = 0.03 \)[/tex]
3. We need to find the approximate value of [tex]\(\rho\)[/tex].

Let's break it down step-by-step:

1. Identify the known values:
- [tex]\( t = 3 \)[/tex]
- [tex]\( f(3) = \rho e^3 = 191.5 \)[/tex]

2. Substitute into the function:
[tex]\[
191.5 = \rho e^3
\][/tex]

3. Solve for [tex]\(\rho\)[/tex]:
- Rearrange the equation to find [tex]\(\rho\)[/tex]:
[tex]\[
\rho = \frac{191.5}{e^3}
\][/tex]

4. Calculate [tex]\(e^3\)[/tex]:
- The value of [tex]\(e^3\)[/tex] is approximately 20.0855.

5. Calculate [tex]\(\rho\)[/tex]:
[tex]\[
\rho = \frac{191.5}{20.0855} \approx 9.53
\][/tex]

6. Find the approximate value of [tex]\(\rho\)[/tex]:
- By rounding [tex]\(\rho\)[/tex], we find that the approximate value is 10.

Therefore, the approximate value of [tex]\(\rho\)[/tex] is closest to 10, which matches none of the given choices. If [tex]\(P\)[/tex] represents this approximate value, it seems there might be an error or discrepancy with the original choices, since none of them exactly match 10.