High School

A polynomial [tex] f(x) [/tex] and two of its zeros are given:

[tex]
f(x) = 5x^5 + 39x^4 + 102x^3 + 18x^2 - 203x + 39
[/tex]

The given zeros are [tex] -3 - 2i [/tex] and [tex] \frac{1}{5} [/tex].

(a) Find all the zeros. Write the answer in exact form. If there is more than one answer, separate them with commas. Select "None" if applicable.

The zeros of [tex] f(x) [/tex] are: [tex] \square [/tex]

Answer :

To find all the zeros of the polynomial [tex]\( f(x) = 5x^5 + 39x^4 + 102x^3 + 18x^2 - 203x + 39 \)[/tex], given that two of its zeros are [tex]\(-3 - 2i\)[/tex] and [tex]\(\frac{1}{5}\)[/tex], let's proceed with the following steps:

### Step 1: Identify the complex conjugate pair

Since the coefficients of the polynomial are real numbers, the complex roots must occur in conjugate pairs. Therefore, if [tex]\(-3 - 2i\)[/tex] is a root, its complex conjugate [tex]\(-3 + 2i\)[/tex] is also a root.

### Step 2: Represent the known roots as factors

We have the following factors for the known zeros:
- For the root [tex]\(-3 - 2i\)[/tex], the factor is [tex]\( (x - (-3 - 2i)) = (x + 3 + 2i) \)[/tex].
- For the root [tex]\(-3 + 2i\)[/tex], the factor is [tex]\( (x - (-3 + 2i)) = (x + 3 - 2i) \)[/tex].
- For the root [tex]\(\frac{1}{5}\)[/tex], the factor is [tex]\( (x - \frac{1}{5}) \)[/tex].

### Step 3: Multiply the complex conjugate factors

Multiply the factors of the complex conjugate roots to form a quadratic factor:

[tex]\[
(x + 3 + 2i)(x + 3 - 2i) = ((x + 3)^2 - (2i)^2) = (x + 3)^2 + 4
\][/tex]

Calculate [tex]\((x + 3)^2 = x^2 + 6x + 9\)[/tex]. Thus, the quadratic factor is:

[tex]\[
x^2 + 6x + 9 + 4 = x^2 + 6x + 13
\][/tex]

### Step 4: Form the polynomial from the known factors

The polynomial formed from the known zeros is:

[tex]\[
(x^2 + 6x + 13)\left(x - \frac{1}{5}\right) = (5x^2 + 30x + 65)(x - \frac{1}{5})
\][/tex]

### Step 5: Divide the original polynomial

Now, divide the original polynomial by the product of the known factors to find the remaining polynomial factor:

1. Divide [tex]\(5x^5 + 39x^4 + 102x^3 + 18x^2 - 203x + 39\)[/tex] by [tex]\((5x^3 + 25x^2 + 32x + 13)\)[/tex].

2. Use synthetic or long division to perform the division. The result should be a quadratic polynomial.

### Step 6: Factor the remaining polynomial

Factor the remaining quadratic polynomial to find the other zeros. The zeros will be real or complex numbers that, along with the known zeros, make up the entire set of zeros for the polynomial [tex]\( f(x) \)[/tex].

Completing all these steps should yield all the zeros of the polynomial in exact form. If you have difficulties with the division or factoring process, please feel free to ask for further clarification or additional help with specific steps!