Answer :
To find the stopping distance for a car traveling at 35 mph on a wet road, we use the formula:
[tex]\[ d(v) = \frac{2.15 \cdot v^2}{64.4 \cdot f} \][/tex]
Let's break this down step-by-step:
1. Identify the Variables:
- [tex]\( v \)[/tex] is the speed of the car in mph. Here, [tex]\( v = 35 \)[/tex] mph.
- [tex]\( f \)[/tex] is the coefficient of friction. Since it's not provided, we assume it to be 1.
2. Substitute the Values:
- Substitute [tex]\( v = 35 \)[/tex] into the formula.
- We assume [tex]\( f = 1 \)[/tex] since it's unspecified.
3. Perform the Calculation:
- First, calculate [tex]\( v^2 \)[/tex]: [tex]\( 35^2 = 1225 \)[/tex].
- Multiply [tex]\( 1225 \)[/tex] by [tex]\( 2.15 \)[/tex]: [tex]\( 1225 \times 2.15 = 2637.75 \)[/tex].
- Divide the result by [tex]\( 64.4 \times 1 \)[/tex] (since [tex]\( f = 1 \)[/tex]):
[tex]\[ \frac{2637.75}{64.4} = 40.90 \][/tex]
4. Result:
- The approximate stopping distance for a car traveling at 35 mph on a wet road is about 40.9 feet.
Therefore, the correct answer is approximately 40.9 feet.
[tex]\[ d(v) = \frac{2.15 \cdot v^2}{64.4 \cdot f} \][/tex]
Let's break this down step-by-step:
1. Identify the Variables:
- [tex]\( v \)[/tex] is the speed of the car in mph. Here, [tex]\( v = 35 \)[/tex] mph.
- [tex]\( f \)[/tex] is the coefficient of friction. Since it's not provided, we assume it to be 1.
2. Substitute the Values:
- Substitute [tex]\( v = 35 \)[/tex] into the formula.
- We assume [tex]\( f = 1 \)[/tex] since it's unspecified.
3. Perform the Calculation:
- First, calculate [tex]\( v^2 \)[/tex]: [tex]\( 35^2 = 1225 \)[/tex].
- Multiply [tex]\( 1225 \)[/tex] by [tex]\( 2.15 \)[/tex]: [tex]\( 1225 \times 2.15 = 2637.75 \)[/tex].
- Divide the result by [tex]\( 64.4 \times 1 \)[/tex] (since [tex]\( f = 1 \)[/tex]):
[tex]\[ \frac{2637.75}{64.4} = 40.90 \][/tex]
4. Result:
- The approximate stopping distance for a car traveling at 35 mph on a wet road is about 40.9 feet.
Therefore, the correct answer is approximately 40.9 feet.
