Answer :
To solve the given problem, we need to evaluate the formula using the logical XOR operation. The formula looks like this:
`=X O R(120<102 ; 83=83 ; 51<24)`
The XOR operation outputs TRUE if an odd number of conditions are TRUE, and FALSE if an even number of conditions are TRUE. Let's evaluate each condition step by step:
1. Condition 1: `120 < 102`
- This statement is FALSE because 120 is greater than 102.
2. Condition 2: `83 = 83`
- This statement is TRUE because 83 is equal to 83.
3. Condition 3: `51 < 24`
- This statement is FALSE because 51 is greater than 24.
Now, we have:
- Condition 1: FALSE
- Condition 2: TRUE
- Condition 3: FALSE
With these evaluations:
- XOR needs to be performed on these results: FALSE, TRUE, and FALSE.
Since XOR outputs TRUE only when there is an odd number of TRUE values, let's count:
- We have one TRUE value (from Condition 2) among the three conditions.
Because there is an odd number (1 in this case) of TRUE values, the result of the XOR operation is TRUE.
Therefore, the output of the formula is A. TRUE.
`=X O R(120<102 ; 83=83 ; 51<24)`
The XOR operation outputs TRUE if an odd number of conditions are TRUE, and FALSE if an even number of conditions are TRUE. Let's evaluate each condition step by step:
1. Condition 1: `120 < 102`
- This statement is FALSE because 120 is greater than 102.
2. Condition 2: `83 = 83`
- This statement is TRUE because 83 is equal to 83.
3. Condition 3: `51 < 24`
- This statement is FALSE because 51 is greater than 24.
Now, we have:
- Condition 1: FALSE
- Condition 2: TRUE
- Condition 3: FALSE
With these evaluations:
- XOR needs to be performed on these results: FALSE, TRUE, and FALSE.
Since XOR outputs TRUE only when there is an odd number of TRUE values, let's count:
- We have one TRUE value (from Condition 2) among the three conditions.
Because there is an odd number (1 in this case) of TRUE values, the result of the XOR operation is TRUE.
Therefore, the output of the formula is A. TRUE.
