Answer :
Answer: Assuming the following:
Balanced chemical equation: 3H₂(g) + N₂(g) → 2NH₃(g)
Molar masses: H₂ = 2.02 g/mol, N₂ = 28.02 g/mol, NH₃ = 17.03 g/mol
Calculations:
Calculate moles of reactants:
Moles of H₂ = 2.00 g / 2.02 g/mol = 0.990 mol
Moles of N₂ = 10.1 g / 28.02 g/mol = 0.360 mol
Determine limiting reactant:
Based on the balanced equation, 3 moles of H₂ react with 1 mole of N₂.
For 0.360 mol of N₂, we need 3 * 0.360 = 1.08 mol of H₂.
Since we only have 0.990 mol of H₂, H₂ is the limiting reactant.
Calculate the theoretical yield of NH3:
From the balanced equation, 3 moles of H₂ produce 2 moles of NH₃.
So, 0.990 mol of H₂ will produce (2/3) * 0.990 = 0.660 mol of NH₃.
Convert moles of NH3 to grams:
Mass of NH₃ = 0.660 mol * 17.03 g/mol = 11.24 grams
Therefore, the theoretical yield of NH3 is 11.24 grams.
Explanation:
