College

A certain car has a fuel efficiency of 39.1 miles per gallon (mi/gal). Express this efficiency in kilometers per liter (km/L).

Answer :

The fuel efficiency of the car, which is 39.1 miles per gallon (mi/gal), is equivalent to approximately 16.6 kilometers per liter (km/L).

- To convert miles per gallon (mi/gal) to kilometers per liter (km/L), we use the conversion factor:

1 mile = 1.60934 kilometers and 1 gallon = 3.78541 liters.

- Therefore, the conversion can be calculated as follows:

Efficiency in km/L = (Efficiency in mi/gal) × (1.60934 km/mile) / (3.78541 L/gal)

Efficiency in km/L ≈ (39.1 mi/gal) × (1.60934 km/mile) / (3.78541 L/gal)

Efficiency in km/L ≈ 16.6 km/L

Complete Question:

A certain car has a fuel efficiency of 39.1 miles per gallon (mi/gal).

Express this efficiency in kilometers per liter (km/L).