High School

A car's gasoline tank has the shape of a right rectangular box with a square base whose sides measure 51.7 cm. Its capacity is 52.8 L. If the tank has only 2.33 L remaining, how deep is the gasoline in the tank, assuming the car is parked on level ground?

Answer :

The depth of gasoline in the tank, with 2.33 L remaining, is approximately 8.6 centimeters.

To find the depth of gasoline in the tank, we can first calculate the volume of gasoline in the tank when it has 2.33 L remaining, and then determine the depth based on the shape of the tank.

Side of the square base = 51.7 cm = 0.517 m (since 1 cm = 0.01 m)

Volume of tank = 0.517 m × 0.517 m × height (since it's a square base)

Capacity = 52.8 L = 0.0528 m^3 (since 1 L = 0.001 m^3)

0.0528 m^3 = 0.517 m × 0.517 m × height

Now, solve for height:

height = 0.0528 m / (0.517 m × 0.517 m) ≈ 1.93 m

Remaining gasoline volume = 2.33 L = 0.00233 m^3 (since 1 L = 0.001 m^3)

Depth = 0.00233 m^3 / (0.517 m × 0.517 m)

Depth ≈ 0.0086 m

Therefore, the depth of gasoline in the tank, assuming the car is parked on level ground, is approximately 0.0086 meters or 8.6 centimeters.