High School

A scientist removed a sample of 39.1 g of a chemical from a container. The sample was \( 5 \frac{3}{4} \) g less than three times the total mass of the chemical nicotine.

What was the total mass in grams of the chemical nicotine before the scientist removed the sample of 39.1 grams?

Answer :

To find the total mass of nicotine before a 39.1 g sample was removed, we solve the equation 3x - 5.75 = 39.1, which gives us the total mass as 14.95 g.

The student has provided information about the mass of a chemical sample that was taken from a container and its relationship to the total mass of nicotine. To determine the total mass of the chemical nicotine before the 39.1 g sample was removed, we set up the following equation based on the given data: Let x be the total mass of nicotine in the container. According to the problem, a sample that is 5 3/4 g less than three times the total mass was removed, leading to the equation 3x - 5.75 = 39.1. Solving this equation for x gives us the total mass of the nicotine before the sample was removed.

To solve for x, we add 5.75 to both sides of the equation to get 3x = 44.85 and then divide both sides by 3, resulting in x = 14.95 g. Therefore, the total mass of the nicotine in the container before the sample was removed was 14.95 g.