Answer :
Final answer:
Using the kinematic equation v^2 = u^2 + 2as, it was calculated that the hammer was dropped from a height of 1 foot, which does not match any of the provided answer options.
Explanation:
To determine the height from which the hammer was dropped, we can use the kinematic equation:
v^2 = u^2 + 2as,
where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity, and s is the distance fallen. The hammer hits the floor at 8 ft/s, and the initial velocity (u) is 0 ft/s since the hammer is dropped, so the equation becomes:
8^2 = 0^2 + 2 × 32 × s
64 = 64s
s = 1 ft
Therefore, the hammer was dropped from a height of 1 foot, which is not any of the provided options (A) 16 ft (B) 24 ft (C) 32 ft (D) 40 ft. It seems there might be an error in the provided question or the answer options.
